Goose 0 Posted August 9, 2003 Stardate:213605.10 Transporter Pads Lets just say that the Enterprise has 10 transporter pads which can transport 10 people each. To operate all of those pads simultaneously would require AT LEAST: 4.8 x 10^31 bytes Let's put this in today's terms: 4.8 x 10^31 bytes is: TEN TRILLION TRILLION CD ROMS (uncompressed) About 100 QUINTILLION times more RAM than is availale in all computers on the Earth today. A string of 4MB simms 113 MILLION LIGHT YEARS long. -or- 500 QUADRILLION football fields covered 100 feet deep in 4 MB simms -or- 200 BILLION copies of all the hollywood films ever made digitized at 30 fps into 1600x1200x24 bit images. -or- 2 1/2 COPIES OF WINDOWS NT. Share this post Link to post Share on other sites